What If We Powered Trains by Towing Them with Giant Underground Loops of Liquid Metal?

2026-06-09

Conventional electric trains take power from overhead catenary wires — copper strung at 25 kV, requiring substations every 30-50 km, plus the train carries motors, transformers, and pantographs. What if instead, the track itself moved? Imagine a closed loop of liquid gallium-indium-tin (galinstan) circulating through a tube under the rails at 200 km/h, with each train magnetically coupled to the moving fluid like a fish caught in a current.

The physics is sound: galinstan is liquid at room temperature (melts at -19°C), has a density of 6440 kg/m³, and crucially, is highly conductive (3.46 × 10⁶ S/m). You pump it with magnetohydrodynamic (MHD) drives at power stations every few hundred kilometers, and trains couple to it via linear induction — essentially treating the moving liquid as the secondary of a giant linear motor.

The Pumping Problem

Consider a 1000 km corridor with a tube of cross-section 0.5 m² (a 0.8 m diameter pipe). Total liquid metal volume: 500,000 m³, mass 3.2 × 10⁹ kg — about 3.2 million tonnes. Just accelerating this from rest to 200 km/h (55.6 m/s) takes:

KE = ½mv² = ½ × 3.2×10⁹ × 55.6² = 4.95 × 10¹² J ≈ 1.4 GWh

That's startup cost. Steady-state is worse. Viscous drag in the pipe (galinstan viscosity ≈ 2.4 mPa·s, ~2× water) at Reynolds number ~10⁸ gives a Darcy friction factor of ~0.008. Pressure drop per kilometer:

ΔP/L = f × (ρv²/2D) = 0.008 × (6440 × 3088 / 1.6) ≈ 99 kPa/km

Over 1000 km: 99 MPa total head loss. Power to overcome this: P = ΔP × Q = 9.9×10⁷ × 27.8 m³/s = 2.75 GW. That's a large nuclear reactor's output just to keep the metal moving — before any train draws power.

Coupling to Trains

Here's the elegance: a train doesn't need motors. A superconducting magnet underneath generates a field perpendicular to flow; by Lenz's law, the flowing conductor (galinstan) drags the train forward. To extract 5 MW per train (cruise power for an ICE-class trainset), with field B = 2 T across a 10 m² coupling area, induced current density needed:

F = BIL → 5×10⁶ W / 55.6 m/s = 90 kN drag → I = F/(BL) ≈ 4500 A

Entirely feasible with modern HTS magnets.

Why This Fails (Spectacularly)

The interesting insight: this is a distributed flywheel. That 1.4 GWh of kinetic energy is grid storage — you could regen-brake trains into it, and tap it during peak demand. Suddenly the "stupid" idea becomes a continent-scale battery that happens to move trains.

Key Takeaway: Moving the track instead of the train is physically possible but economically absurd — unless you reframe the multi-gigawatt-hour liquid-metal loop as grid storage that incidentally provides traction.

All newsletters